12x^2-60x+70=0

Solution for 12x^2-60x+70=0 equation:

12x^2-60x+70=0

a = 12; b = -60; c = +70;
Δ = b2-4ac
Δ = -602-4·12·70
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{15}}{2*12}=\frac{60-4\sqrt{15}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{15}}{2*12}=\frac{60+4\sqrt{15}}{24}
$